Answer
$(r+5)(2s-1)$
Work Step by Step
Using factoring by grouping, then,
\begin{array}{l}
2sr+10s-r-5
\\=
(2sr+10s)-(r+5)
\\=
2s(r+5)-(r+5)
\\=
(r+5)(2s-1)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 48
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