Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 99c

Answer

$F(a+h-F(a)=h^2+2ah+3h$

Work Step by Step

Combining the results of (a) and (b), then $F(a+h)-F(a)$ is equal to \begin{array}{l}\require{cancel} (a^2+2ah+h^2+3a+3h+2)-(a^2+3a+2) \\\\= a^2+2ah+h^2+3a+3h+2-a^2-3a-2 \\\\= \cancel{(a^2-a^2)}+2ah+h^2+\cancel{(3a-3a)}+3h+\cancel{(2-2)} \\\\= h^2+2ah+3h \end{array}
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