## Intermediate Algebra (6th Edition)

$2x$ and $3x$ cannot be added together as $3x$ has to be multiplied to $12-x$.
$2x$ and $3x$ cannot be added together as $3x$ has to be multiplied to $12-x$. The correct solution is: $=2x+(3x)(12)-(3x)(x) \\=2x+36x-3x^2 \\=38x-3x^2 \\=-3x^2+38x$