Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 100c



Work Step by Step

Using the results of (a) and (b), then $g(a+h)-g(a)$ is equal to \begin{array}{l}\require{cancel} a^2+2ah+h^2+2a+2h+1-(a^2+2a+1) \\\\= a^2+2ah+h^2+2a+2h+1-a^2-2a-1 \\\\= \cancel{a^2}+2ah+h^2+\cancel{2a}+2h+\cancel{1}- \cancel{a^2}-\cancel{2a}-\cancel{1} \\\\= h^2+2ah+2h .\end{array}
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