Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 103



Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method and using the laws of exponents, the given expression, $ (x^a+5)(x^{2a}-3) $, is equivalent to \begin{array}{l}\require{cancel} x^{a+2a}-3x^a+5x^{2a}-15 \\\\= x^{3a}+5x^{2a}-3x^a-15 .\end{array}
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