Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 100a

Answer

$g(a+h)=a^2+2ah+h^2+2a+2h+1$

Work Step by Step

Replacing $x$ with $a+h$ in the given function, $ g(x)=x^2+2x+1 $, then $g(a+h)$ is equal to, \begin{array}{l} (a+h)^2+2(a+h)+1 \\\\= (a^2+2ah+h^2)+(2a+2h)+1 \\\\= a^2+2ah+h^2+2a+2h+1 \end{array}
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