Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 102



Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property and using the laws of exponents, the given expression, $ -3yz^n(2y^3z^{2n}-1) $, simplifies to \begin{array}{l}\require{cancel} -6y^{1+3}z^{n+2n}+3yz^n \\\\= -6y^{4}z^{3n}+3yz^n .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.