Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 197: 95



Work Step by Step

Using the properties of equality, the given equation, $ 4x+3y=5 ,$ is equivalent to \begin{array}{l} 3y=-4x+5 \\\\ y=-\dfrac{4}{3}x+\dfrac{5}{3} .\end{array} Using $y=mx+b$, where $m$ is the slope, the slope of the given line is \begin{array}{l} m=-\dfrac{4}{3} .\end{array} Using $m= \dfrac{3}{4} $ (negative reciprocal slope since the lines are perpendicular) and the given point $( -6,-1 ),$ then the equation of the line is \begin{array}{l} y-(-1)=\dfrac{3}{4}(x-(-6)) \\\\ y+1=\dfrac{3}{4}(x+6) \\\\ y+1=\dfrac{3}{4}x+\dfrac{18}{4} \\\\ y=\dfrac{3}{4}x+\dfrac{18}{4}-1 \\\\ y=\dfrac{3}{4}x+\dfrac{18}{4}-\dfrac{4}{4} \\\\ y=\dfrac{3}{4}x+\dfrac{14}{4} \\\\ y=\dfrac{3}{4}x+\dfrac{7}{2} .\end{array} In function notation, this is equivalent to $ f(x)=\dfrac{3}{4}x+\dfrac{7}{2} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.