## Intermediate Algebra (6th Edition)

$y=-5$
A line parallel to $y=8$ has a slope of $0$. Using $y-y_1=m(x-x_1)$ or the Point-Slope Form, the equation of the line with slope $0$ and passing through $(-2,-5)$ is \begin{array}{l} y-(-5)=0(x-(-2)) \\\\ y+5=0 \\\\ y=-5 .\end{array}