Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 197: 106

Answer

see graph
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Work Step by Step

Changing the given inequality, $ \dfrac{1}{2}x-y\lt2 ,$ to equality and then isolating $y$ result to \begin{array}{l}\require{cancel} \dfrac{1}{2}x-y=2 \\\\ -y=-\dfrac{1}{2}x+2 \\\\ y=\dfrac{1}{2}x-2 .\end{array} Use the table of values below to graph this line. Since the inequality used is "$ \lt $", use broken lines. Using the test point $( 0,0 )$, then \begin{array}{l}\require{cancel} \dfrac{1}{2}(0)-0\lt2 \\\\ 0\lt2 \text{ (TRUE)} .\end{array} Since the solution above ended with a $\text{ TRUE }$ statement, then the test point is $\text{ part }$ of the solution set.
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