## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Review - Page 197: 87

#### Answer

$x+2y=-8$

#### Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-PointForm, the equation of the line passing through $( -6,-1 )$ and $( -4,-2 )$ is \begin{array}{l} y-(-1)=\dfrac{-1-(-2)}{-6-(-4)}(x-(-6)) \\\\ y+1=\dfrac{-1+2}{-6+4}(x+6) \\\\ y+1=\dfrac{1}{-2}(x+6) \\\\ -2(y+1)=1(x+6) \\\\ -2y-2=x+6 \\\\ -x-2y=6+2 \\\\ -x-2y=8 \\\\ x+2y=-8 .\end{array}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.