## Intermediate Algebra (6th Edition)

$y=\dfrac{3}{4}x+2$
Using $y-y_1=m(x-x_1)$ or the Point-Slope Form, the equation of the line with slope $\dfrac{3}{4}$ and passing through $\left( -8,-4 \right)$ is \begin{array}{l} y-(-4)=\dfrac{3}{4}(x-(-8)) \\\\ y+4=\dfrac{3}{4}(x+8) \\\\ y+4=\dfrac{3}{4}x+6 \\\\ y=\dfrac{3}{4}x+6-4 \\\\ y=\dfrac{3}{4}x+2 .\end{array}