Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 197: 121



Work Step by Step

Using $y=mx+b$, where $m$ is the slope, the slope of the given line, $ y=-\dfrac{3}{2}x+11 $ is \begin{array}{l} m=-\dfrac{3}{2} .\end{array} Using $m= -\dfrac{3}{2} $ (parallel lines have same slope) and the given point $( -6,1 ),$ then the equation of the line is \begin{array}{l} y-1=-\dfrac{3}{2}(x-(-6)) \\\\ y-1=-\dfrac{3}{2}(x+6) \\\\ y-1=-\dfrac{3}{2}x-9 \\\\ y=-\dfrac{3}{2}x-9+1 \\\\ y=-\dfrac{3}{2}x-8 .\end{array}
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