## Intermediate Algebra (6th Edition)

$y=-\dfrac{3}{2}x-8$
Using $y=mx+b$, where $m$ is the slope, the slope of the given line, $y=-\dfrac{3}{2}x+11$ is \begin{array}{l} m=-\dfrac{3}{2} .\end{array} Using $m= -\dfrac{3}{2}$ (parallel lines have same slope) and the given point $( -6,1 ),$ then the equation of the line is \begin{array}{l} y-1=-\dfrac{3}{2}(x-(-6)) \\\\ y-1=-\dfrac{3}{2}(x+6) \\\\ y-1=-\dfrac{3}{2}x-9 \\\\ y=-\dfrac{3}{2}x-9+1 \\\\ y=-\dfrac{3}{2}x-8 .\end{array}