Intermediate Algebra (6th Edition)

$y=-5x-7$
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, the equation of the line passing through $( -3,8 )$ and $( -2,3 )$ is \begin{array}{l} y-8=\dfrac{8-3}{-3-(-2)}(x-(-3)) \\\\ y-8=\dfrac{5}{-1}(x+3) \\\\ y-8=-5(x+3) \\\\ y-8=-5x-15 \\\\ y=-5x-15+8 \\\\ y=-5x-7 .\end{array}