## Intermediate Algebra (6th Edition)

Using the properties of equality, the first equation, $x-2y=6 ,$ is equivalent to \begin{array}{l} -2y=-x+6 \\\\ y=\dfrac{-1}{-2}x+\dfrac{6}{-2} \\\\ y=\dfrac{1}{2}x-3 .\end{array} Using $y=mx+b$, where $m$ is the slope, the slope is \begin{array}{l} m_1=\dfrac{1}{2} .\end{array} Using the properties of equality, the second equation, $4x+y=8 ,$ is equivalent to \begin{array}{l} y=-4x+8 .\end{array} Using $y=mx+b$, where $m$ is the slope, the slope is \begin{array}{l} m_2=-4 .\end{array} Since $m_1\ne m_2,$ and $m_1\cdot m_2\ne-1$ then the given lines are $\text{ neither parallel nor perpendicular .}$