Intermediate Algebra (6th Edition)

Substituting $y=0$ in the given equation, $4x-y=3 ,$ then \begin{array}{l}\require{cancel} 4x-0=3 \\\\ 4x=3 \\\\ x=\dfrac{3}{4} .\end{array} The $x-$intercept is $\left( \dfrac{3}{4} ,0\right)$. Substituting $x=0$ in the given equation then \begin{array}{l}\require{cancel} 4(0)-y=3 \\\\ -y=3 \\\\ y=-3 .\end{array} The $y-$intercept is $\left(0, -3 \right)$. Using the intercepts, the graph is shown above.