Answer
see graph
Work Step by Step
Substituting $y=0$ in the given equation, $
4x-y=3
,$ then
\begin{array}{l}\require{cancel}
4x-0=3
\\\\
4x=3
\\\\
x=\dfrac{3}{4}
.\end{array}
The $x-$intercept is $\left(
\dfrac{3}{4}
,0\right)$.
Substituting $x=0$ in the given equation then
\begin{array}{l}\require{cancel}
4(0)-y=3
\\\\
-y=3
\\\\
y=-3
.\end{array}
The $y-$intercept is $\left(0,
-3
\right)$.
Using the intercepts, the graph is shown above.
