## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Review - Page 196: 72

perpendicular

#### Work Step by Step

Using $y=mx+b$, where $m$ is the slope, the slope of $y=\dfrac{3}{4}x+1$ is \begin{array}{l} m_1=\dfrac{3}{4} \end{array} and the slope of $y=-\dfrac{4}{3}x+1$ is \begin{array}{l} m_2=-\dfrac{4}{3} .\end{array} Since $m_1\cdot m_2=-1,$ then the given lines are $\text{ perpendicular .}$

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