## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Review - Page 196: 50

see graph

#### Work Step by Step

Substituting $y=0$ in the given equation, $2x+6y=9 ,$ then \begin{array}{l}\require{cancel} 2x+6(0)=9 \\\\ 2x=9 \\\\ x=\dfrac{9}{2} .\end{array} The $x-$intercept is $\left( \dfrac{9}{2} ,0\right)$. Substituting $x=0$ in the given equation then \begin{array}{l}\require{cancel} 2(0)+6y=9 \\\\ 6y=9 \\\\ y=\dfrac{9}{6} \\\\ y=\dfrac{3}{2} .\end{array} The $y-$intercept is $\left(0, \dfrac{3}{2} \right)$. Using the intercepts, the graph is shown above.

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