Answer
see graph
Work Step by Step
Using $y=mx+b$, the given equation, $
y=4x-3
,$ has the following characteristics:
\begin{array}{l}\require{cancel}
\text{Slope: }
m=4
\\\text{$y$-intercept: }
b=-3
.\end{array}
To graph this line, start with the $y-$intercept of $(
0,-3
)$. From the $y-$intercept, the slope, $m=
4=\dfrac{4}{1}
$ can be interpreted as moving $4$ units up and $1$ unit to the right. Hence, the second point for graphing is the point $(
1,1
)$.
