## Intermediate Algebra (6th Edition)

Substituting $y=0$ in the given equation, $4x+5y=20 ,$ then \begin{array}{l}\require{cancel} 4x+5(0)=20 \\\\ 4x=20 \\\\ x=\dfrac{20}{4} \\\\ x=5 .\end{array} The $x-$intercept is $( 5 ,0)$. Substituting $x=0$ in the given equation then \begin{array}{l}\require{cancel} 4(0)+5y=20 \\\\ 5y=20 \\\\ y=\dfrac{20}{5} \\\\ y=4 .\end{array} The $y-$intercept is $(0, 4 )$. Using the intercepts, the graph is shown above.