## Intermediate Algebra (6th Edition)

Substituting $y=0$ in the given equation, $3x-2y=-9 ,$ then \begin{array}{l}\require{cancel} 3x-2(0)=-9 \\\\ 3x=-9 \\\\ x=-\dfrac{9}{3} \\\\ x=-3 .\end{array} The $x-$intercept is $( -3 ,0)$. Substituting $x=0$ in the given equation then \begin{array}{l}\require{cancel} 3(0)-2y=-9 \\\\ -2y=-9 \\\\ y=\dfrac{-9}{-2} \\\\ y=\dfrac{9}{2} .\end{array} The $y-$intercept is $\left(0, \dfrac{9}{2} \right)$. Using the intercepts, the graph is shown above.