Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 100: 8

Answer

n=6 n=-18

Work Step by Step

Original Equation |$\frac{n}{3}$+2|=4 Take $\frac{n}{3}$+2 and solve $\frac{n}{3}$+2=4 Multiply both sides by 3 n+6=12 Subtract 6 from both sides n=6 Make $\frac{n}{3}$+2 negative and solve -$\frac{n}{3}$-2=4 Multiply both sides by -3 n+6=-12 Subtract 6 from both sides n=-18
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