Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 100: 18

Answer

y=-$\frac{2}{3}$

Work Step by Step

Original Equation |3y+2|=0 Take 3y+2 and solve 3y+2=0 Subtract 2 from both sides 3y=-2 Divide both sides by 3 y=-$\frac{2}{3}$ Make 3y+2 negative and solve -3y-2=0 Add 2 to both sides -3y=2 Divide both sides by -3 y=-$\frac{2}{3}$
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