## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set: 61

#### Answer

$y = 2, y = 3$

#### Work Step by Step

$\mid$$2y - 3$$\mid$ $=$ $\mid$$9 - 4y$$\mid$ $2y - 3 = 9 - 4y$ $6y = 12$ $y = 2$ $\mid$$2y - 3$$\mid$ $=$ $\mid$$9 - 4y$$\mid$ $2y - 3 = -9 + 4y$ $-2y = -6$ $y = 3$

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