Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 100: 56

Answer

Solutions are $5, \frac{-17}{3}$

Work Step by Step

$|\frac{1+3n}{4}| = 4$ This is equivalent to $\frac{1+3n}{4} = 4$ or $\frac{1+3n}{4} = -4$ $1+3n = 16$ or $1+3n = -16$ $3n = 15$ or $3n = -16-1$ $n= 5 $ or $ 3n = -17$ $n= 5 $ or $ n= \frac{-17}{3}$ Solutions are $5, \frac{-17}{3}$
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