## Intermediate Algebra (6th Edition)

Solutions are $13,-8$
$|\frac{2x-5}{3}| = 7$ We can write it as $\frac{2x-5}{3}= 7$ or $\frac{2x-5}{3} = -7$ $2x-5 = 21$ or $2x-5 = -21$ $2x = 21 +5$ or $2x = -21+5$ $2x = 26$ or $2x=-16$ $x= 13$ or $x=-8$ Solutions are $13,-8$.