Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 100: 46


c=$\frac{3}{2}$ c=$\frac{7}{6}$

Work Step by Step

Original Equation |8-6c|=1 Take 8-6c and solve 8-6c=1 Subtract 8 from both sides -6c=-7 Divide both sides by -6 c=$\frac{7}{6}$ Make 8-6c negative and solve -8+6c=1 Add 8 to both sides 6c=9 Divide both sides by 6 c=$\frac{3}{2}$
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