Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set - Page 100: 32

Answer

z=3 z=-3

Work Step by Step

Original Equation |7z|+1=22 Subtract 1 from both sides |7z|=21 Take 7z and solve 7z=21 Divide both sides by 7 z=3 Make 7z negative and solve -7z=21 Divide both sides by -7 z=-3
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