## Intermediate Algebra (6th Edition)

$x=-\frac{3}{22}$
We are given the equation $7x^{2}+2x-3=6x(x+4)+x^{2}$. We can solve for x by first using the distributive property to simplify the right side. $7x^{2}+2x-3=6x\times(x+4)+x^{2}=6x^{2}+24x+x^{2}$ Group like terms on the right side. $7x^{2}+2x-3=7x^{2}+24x$ Subtract $7x^{2}$ from both sides. $2x-3=24x$ Subtract 2x from both sides. $-3=22x$ Divide both sides by 22. $x=-\frac{3}{22}$