Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 92



Work Step by Step

We are given the equation $7x^{2}+2x-3=6x(x+4)+x^{2}$. We can solve for x by first using the distributive property to simplify the right side. $7x^{2}+2x-3=6x\times(x+4)+x^{2}=6x^{2}+24x+x^{2}$ Group like terms on the right side. $7x^{2}+2x-3=7x^{2}+24x$ Subtract $7x^{2}$ from both sides. $2x-3=24x$ Subtract 2x from both sides. $-3=22x$ Divide both sides by 22. $x=-\frac{3}{22}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.