Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 56: 64



Work Step by Step

$\frac{1}{5}(2y-1)-2=\frac{1}{2}(3y-3)+3$ $\frac{2}{5}y-\frac{1}{5}-2=\frac{3}{2}y-\frac{5}{2}+3$ $4y-15y=30+20-25+2$ $-11y=27$ $y=-\frac{27}{11}$
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