Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 56: 86



Work Step by Step

We are given the equation $-7.6y-10=-1.1y+12$ and the equation $-7.6y=-1.1y+K$ In order to find the value of K that makes both equations equivalent, we must move all constant terms in the first equation to the right side. For $-7.6y-10=-1.1y+12$, add 10 to both sides. $-7.6y=-1.1y+22$. Therefore, both equations will be equivalent when $K=22$.
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