Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 56: 88



Work Step by Step

We are given the equation $\frac{x}{6}+4=\frac{x}{3}$ and the equation $x+K=2x$ In order to find the value of K that makes both equations equivalent, we must multiply each term in the first equation by 6 (the least common denominator of all terms) in order to get rid of fractions. $\frac{x}{6}\times6+4\times6=\frac{x}{3}\times6$ $x+24=2x$ Therefore, $K=24$
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