Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 56: 63



Work Step by Step

$\frac{1}{3}(y+4)+6=\frac{1}{4}(3y-1)-2$ $\frac{1}{3}y+\frac{4}{3}+\frac{18}{3}=\frac{3}{4}y-\frac{1}{4}-\frac{8}{4}$ $-\frac{5}{12}y=-\frac{115}{12}$ $-5y=-115$ $y=23$
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