Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 65

Answer

n=$\frac{-2}{9}$

Work Step by Step

2 [ 7 - 5(1-n) ] + 8n = -16 + 3 [ 6(n+1) - 3n ] 2 [ 7 - 5 + 5n ] + 8n = -16 + 3 [ 6n + 6 - 3n ] 2 [ 2 + 5n ] + 8n = -16 + 3 [ 3n + 6 ] 4 + 10n + 8n = -16 + 9n +18 18n + 4 = 9n + 2 9n = -2 n=$\frac{-2}{9}$
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