Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 56: 91



Work Step by Step

We are given the equation $x(x-6)+7=x(x+1)$. We can solve for x by first using the distributive property to simplify both sides. $x\times(x-6)+7=x\times(x+1)$ $x^{2}-6x+7=x^{2}+x$ Subtract $x^{2}$ from both sides. $-6x+7=x$ Add 6x to both sides. $7=7x$ Divide both sides by 7. $x=1$
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