Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 60d

Answer

TRUE

Work Step by Step

The results of (a) and (b) show that the constant expression in the summation symbol can be factored out of the summation symbol. Hence, $ \displaystyle\sum_{i=1}^n c\cdot a_n=c\cdot\displaystyle\sum_{i=1}^n a_n $.
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