## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 60d

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#### Work Step by Step

The results of (a) and (b) show that the constant expression in the summation symbol can be factored out of the summation symbol. Hence, $\displaystyle\sum_{i=1}^n c\cdot a_n=c\cdot\displaystyle\sum_{i=1}^n a_n$.

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