Answer
$2,205$
Work Step by Step
The expression $
5\cdot\displaystyle\sum_{i=1}^6 i^3
$ evaluates to
\begin{array}{l}
5[(1)^3+(2)^3+(3)^3+(4)^3+(5)^3+(6)^3]
\\=
5[1+8+27+64+125+216]
\\=
\\=
5[441]
\\=
2,205
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 60b
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