Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 47

Answer

The amount of decay in the fourth year is $6.25 lbs$. The total amount of decay in the first four year is $93.75 lbs$.

Work Step by Step

For the general term of the amount of decay is given by $a_{n} = 100(0.5)^n$ where n is the number of the year, The amount of decay in the fourth year is $a_{4} = 100(0.5)^4 = 6.25 lbs$. The total amount of decay in the first four year = $\sum\limits_{n=1}^4 a_{n} = \sum\limits_{n=1}^4 100(0.5)^n = 50 + 25 + 12.5 + 6.25 = 93.75 lbs$
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