Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 49

Answer

The length of the fifth swing is 16.4 inches (round to the nearest tenth of an inch). The total length swung during the first five swings is 134.5 inches (round to the nearest tenth of an inch).

Work Step by Step

For the pendulum, since each successive swing is $\frac{4}{5}$ of the preceding swing, the situation can be modeled by a geometric sequence with $a_{1} = 40$ and $r = \frac{4}{5}$, and the general term to be $a_{n} = 40(\frac{4}{5})^{n-1}$. For the fifth swing, the length is $a_{5}$ = $40(\frac{4}{5})^{5-1}$ = 16.4 inches (round to the nearest tenth of an inch). And, the total length swung during the first five swings will be $\sum\limits_{n=1}^5 a_{n}$ = $\sum\limits_{n=1}^5 40(\frac{4}{5})^{n-1}$ = 40 + 32 + 25.6 + 20.48 + 16.384 = 134.5 inches (round to the nearest tenth of an inch).
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