## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Section 11.3 - Series - Exercise Set: 60a

#### Answer

$2,205$

#### Work Step by Step

The expression $\displaystyle\sum_{i=1}^6 5i^3$ evaluates to \begin{array}{l} 5(1)^3+5(2)^3+5(3)^3+5(4)^3+5(5)^3+5(6)^3 \\= 5+5(8)+5(27)+5(64)+5(125)+5(216) \\= 5+40+135+320+625+1,080 \\= 2,205 .\end{array}

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