Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 652: 53

Answer

$\frac{10}{27}$

Work Step by Step

Plug in and use PEMDAS (parentheses, exponentiation, multiplication, division, addition, subtraction) to determine which operation goes first. $\frac{\frac{1}{3}}{1-\frac{1}{10}} = \frac{\frac{1}{3}\cdot3}{\frac{9}{10}\cdot3} = \frac{1}{\frac{27}{10}} = \frac{1\cdot10}{\frac{27}{10}\cdot10} = \frac{10}{27}$
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