Answer
Total number of fungus at the end of 5th day : $186$ units
Work Step by Step
Given $a_{n} = 6 \times 2^{n-1}$
$a_{1} = 6 \times 2^{1-1} = 6 \times 2^{0} = 6 \times 1 = 6$
$a_{2} = 6 \times 2^{2-1} = 6 \times 2^{1} = 6 \times 2 = 12$
$a_{3} = 6 \times 2^{3-1} = 6 \times 2^{2} = 6 \times 4 = 24$
$a_{4} = 6 \times 2^{4-1} = 6 \times 2^{3} = 6 \times 8 = 48$
$a_{5} = 6 \times 2^{5-1} = 6 \times 2^{4} = 6 \times 16 = 96$
Total number of fungus at the end of 5th day
$S_{5} = a_{1} + a_{2} + a_{3} +a_{4} +a_{5}$
$S_{5} = 6+ 12 + 24 + 48 + 96$
$S_{5} = 186$ units
