Answer
$\frac{1}{4}, \frac{1}{5}, \frac{1}{6}, \frac{1}{7}, \frac{1}{8}$
Work Step by Step
Let's evaluate $a_1, a_2, a_3, a_4, $and $a_5$ by plugging in $1, 2, 3, 4, $ and $5$ for each $n$.
$a_1 = \frac{1}{1+3} = \frac{1}{4}$
$a_2 = \frac{1}{2+3} = \frac{1}{5}$
$a_3 = \frac{1}{3+3} = \frac{1}{6}$
$a_4 = \frac{1}{4+3} = \frac{1}{7}$
$a_5 = \frac{1}{5+3} = \frac{1}{8}$
