Answer
$-2, 4, -8, 16, -32$
Work Step by Step
Let's evaluate $a_1, a_2, a_3, a_4, $and $a_5$ by plugging in $1, 2, 3, 4, $ and $5$ for each $n$.
$a_1 = (-2)^1 = -2$
$a_2 = (-2)^2 = 4$
$a_3 = (-2)^3 = -8$
$a_4 = (-2)^4 = 16$
$a_5 = (-2)^5 = -32$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 639: 4
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