Answer
$\frac{1}{3}, 1, 3, 9, 27$
Work Step by Step
Let's evaluate $a_1, a_2, a_3, a_4, $and $a_5$ by plugging in $1, 2, 3, 4, $ and $5$ for each $n$.
$a_1 = 3^(1-2) = 3^{-1} = \frac{1}{3}$
$a_2 = 3^(2-2) = 3^0 = 1$
$a_3 = 3^(3-2) = 3^1 = 3$
$a_4 = 3^(4-2) = 3^2 = 9$
$a_5 = 3^(5-2) = 3^3 = 27$
