Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 639: 41

Answer

$a_{n}= 0.10 (2)^{n-1}$ $819.20 $ Dollars

Work Step by Step

Allowance on first day $a_{1}= 0.10 = 0.10 \times 1 = 0.10 \times 2 ^{0}$ Allowance on second day $a_{2}= 0.20 =0.10 \times 2 = 0.10 \times 2 ^{1}$ Allowance on third day $a_{3}= 0.40 =0.10 \times 4 = 0.10 \times 2 ^{2} $ Allowance on fourth day $a_{4}= 0.80 =0.10 \times 8 = 0.10 \times 2 ^{3} $ Allowance on nth day $a_{n}= 0.10 \times 2 ^{n-1} $ Allowance on 14th day $a_{14}= 0.10 \times 2 ^{14-1} $ $a_{14}= 0.10 \times 2 ^{13} $ $a_{14}=0.10 \times 8192$ $a_{14}= 819.20$ Dollars
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