Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 639: 37


$a_n=\left( \dfrac{1}{3} \right)^n$

Work Step by Step

The terms are the powers of $\dfrac{1}{3}$. Hence, a possible general term is \begin{array}{l}\require{cancel} a_n=\left( \dfrac{1}{3} \right)^n .\end{array}
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