Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 639: 34

Answer

$a_{n}=5n-3$

Work Step by Step

Given Sequence: $2,7,12,17$ We can write it as $5-3,10-3,15-3,20-3$ $ a_{1} = 2= 5-3 = 5(1)-3$ $ a_{2} = 7 = 10-3 = 5(2)-3$ $ a_{3} = 12 = 15-3 = 5(3)-3$ $ a_{4} = 17 = 20 -3 = 5(4)-3$ General term : $a_{n}=5(n)-3$
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