## Intermediate Algebra (6th Edition)

$2700, 2850, 3000, 3150,$ and $3300$
The number of students enrolled follows an arithmetic sequence with a common difference of $150$ and a first term of $2700$. The number of students enrolled for the next year can be found by adding the common difference of $150$. Thus, the number of students enrolled for each of 5 years beginning with $2000$ is: Year 2000 $=a_1 = 2700$ Year 2001 $=a_2 = 2700+150=2850$ Year 2002 $=a_3 = 2850+150=3000$ Year 2003 $=a_4 = 3000+150=3150$ Year 2004 $=a_5 = 3150+150=3300$