Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set: 44

Answer

$2700, 2850, 3000, 3150,$ and $3300$

Work Step by Step

The number of students enrolled follows an arithmetic sequence with a common difference of $150$ and a first term of $2700$. The number of students enrolled for the next year can be found by adding the common difference of $150$. Thus, the number of students enrolled for each of 5 years beginning with $2000$ is: Year 2000 $=a_1 = 2700$ Year 2001 $=a_2 = 2700+150=2850$ Year 2002 $=a_3 = 2850+150=3000$ Year 2003 $=a_4 = 3000+150=3150$ Year 2004 $=a_5 = 3150+150=3300$
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