Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Mixed Review Exercises - Page 639: 5

Answer

$-5$

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_33^{-5} ,$ is equivalent to \begin{align*}\require{cancel} & -5\log_33 &(\text{use }\log_b x^y=y\log_b x) \\&= -5(1) &(\text{use }\log_b b=1) \\&= -5 .\end{align*} Hence, the expression $ \log_33^{-5} $ evaluates to $ -5 $.
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